Practice Analytical Reasoning (Logic Games) questions for the Law School Admission Test. Every question includes a full explanation of why the correct answer is right and why the tempting distractors are wrong.
10 example questions with full explanations. Use the interactive practice above to work through the complete set.
Question 1medium
Six employees — M, N, O, P, Q, and R — are assigned to exactly two teams, Team 1 and Team 2, with three employees on each team. The following conditions apply:
- M and N cannot be on the same team.
- If O is on Team 1, then P is on Team 2.
- Q and R must be on the same team.
If M is on Team 1, which of the following could be a complete and accurate list of Team 2's members?
- A.N, Q, R
- B.N, O, R
- C.M, Q, R
- D.N, O, P✓
Correct answer: D
Since M is on Team 1, N must be on Team 2. Q and R must be together. Option C places Team 2 as N, O, P and Team 1 as M, Q, R: N and M are apart ✓; Q and R are together on Team 1 ✓; O is on Team 2, so the rule 'if O on Team 1 then P on Team 2' is not triggered ✓. This is fully valid. Option A puts O on Team 1 (with M and P), which triggers the rule requiring P on Team 2 — but P is on Team 1, a violation. Option B separates Q and R. Option C places M on Team 2, contradicting the given condition. Answer C is the only valid list.
Question 2medium
A project manager schedules six tasks — J, K, L, M, N, and O — one per day across six consecutive days. The following conditions apply:
- K is scheduled sometime before M.
- L and N are scheduled on consecutive days.
- If O is scheduled on day 1, then J is scheduled on day 6.
- J is not scheduled on day 3.
If L is scheduled on day 4 and N is scheduled on day 5, which of the following must be false?
- A.O is scheduled on day 2 and J is scheduled on day 3.✓
- B.K is scheduled on day 1 and M is scheduled on day 6.
- C.O is scheduled on day 1 and J is scheduled on day 6.
- D.J is scheduled on day 2 and O is scheduled on day 6.
Correct answer: A
With L on day 4 and N on day 5, the remaining tasks J, K, M, and O fill days 1, 2, 3, and 6. The rule that J is not on day 3 means J occupies day 1, 2, or 6. Option B: K on day 1, M on day 6. J, O fill days 2 and 3. J cannot be on day 3, so J on day 2 and O on day 3. K (day 1) before M (day 6) ✓; O not on day 1 so the O→J conditional isn't triggered ✓. Valid — could be true. Option C: O on day 1 means J must be on day 6. K and M then fill days 2 and 3, with K before M (K on 2, M on 3) ✓. All rules satisfied — could be true. Option D: J on day 2, O on day 6. K and M fill days 1 and 3, K before M (K on 1, M on 3) ✓; O not on day 1 ✓; J not on day 3 ✓. Valid — could be true. Option A: O on day 2, J on day 3. But the rule explicitly states J cannot be scheduled on day 3. This directly violates a rule and MUST be false. Answer A.
Question 3medium
A project manager must assign exactly five consultants — F, G, H, J, and K — to two teams: Team 1 and Team 2. Each consultant is assigned to exactly one team. Team 1 must have at least two consultants, and Team 2 must have at least two consultants. The following conditions apply:
- If F is on Team 1, then G is on Team 2.
- If H is on Team 2, then J is on Team 1.
- K and G must be on the same team.
If F is on Team 1, which of the following must be true?
- A.H is on Team 1.
- B.K is on Team 2.✓
- C.J is on Team 2.
- D.H is on Team 2.
Correct answer: B
If F is on Team 1, then the first rule forces G onto Team 2. Since K and G must be on the same team (third rule), K must also be on Team 2. This means Team 2 has at least G and K, satisfying the minimum for Team 2, and Team 1 has at least F. The remaining consultants H and J can be distributed freely as long as minimums are met, but K being on Team 2 is guaranteed regardless of where H and J go. Option A and D cannot both be true simultaneously and neither is forced. OptionB(J on Team 2) is not required — J could be on Team 1 or Team 2 without violating any rule (the second rule only restricts J's placement if H is on Team 2, but H's placement is not fixed). OnlyB(K on Team 2) is definitively forced by the chain: F on Team 1 → G on Team 2 → K on Team 2.
Question 4medium
Seven books — L, M, N, O, P, Q, and R — are arranged in a single row on a shelf, numbered positions 1 through 7 from left to right. The following conditions apply:
- L is somewhere to the left of M.
- N is immediately to the right of O.
- P is not in position 1 or position 7.
- Q is somewhere to the right of M.
Which of the following could be an accurate partial arrangement showing books in positions 3, 4, and 5, respectively?
- A.M, Q, L
- B.N, O, M
- C.O, N, P✓
- D.Q, M, L
Correct answer: C
Option B places O in position 3 and N in position 4, which satisfies the rule that N is immediately to the right of O. P is in position 5, which is neither position 1 nor position 7, satisfying that rule. The remaining books L, M, Q, and R fill positions 1, 2, 6, and 7 in some order. L can be in position 1 or 2, M can follow L, and Q can follow M — all consistent with the ordering rules. Option A places M before Q (good) but puts L in position 5, which is to the right of M in position 3, violating the rule that L must be left of M. Option B places N in position 3 and O in position 4, violating the rule that N must be immediately to the RIGHT of O (here N would be to O's left). Option D puts Q in position 3 and M in position 4, but Q must be to the right of M, so Q cannot precede M.
Question 5medium
A photographer must pair exactly four models — 1, 2, 3, and 4 — with exactly four outfits — W, X, Y, and Z — for a photo shoot. Each model is paired with exactly one outfit, and each outfit is used with exactly one model. The following conditions apply:
- Model 1 is not paired with outfit W or outfit Z.
- Model 3 is paired with outfit X or outfit Y.
- If Model 2 is paired with outfit Y, then Model 4 is paired with outfit W.
If Model 3 is paired with outfit Y, which of the following could be true?
- A.Model 2 is paired with outfit Y.
- B.Model 1 is paired with outfit Y.
- C.Model 4 is paired with outfit X, and Model 2 is paired with outfit W.
- D.Model 1 is paired with outfit X, and Model 2 is paired with outfit W.✓
Correct answer: D
If Model 3 is paired with outfit Y, then Y is unavailable to others. Model 1 cannot wear W or Z (first rule), so Model 1 must wear X (the only remaining eligible outfit). Models 2 and 4 must then split outfits W and Z. Option C assigns Model 2 to W and (implicitly) Model 4 to Z — no rule is violated, since the third conditional rule only applies if Model 2 wears Y, which is not the case here. This makes D a valid possibility. Option A is impossible because Y is already assigned to Model 3. Option B is impossible for the same reason. Option C assigns Model 4 to X, but X is already taken by Model 1, making C impossible.
Question 6medium
In a logic game, six students — L, M, N, O, P, and Q — are each assigned to exactly one of two study groups: Group 1 or Group 2. Each group must have at least two students. The following rules apply:
- L and M cannot be in the same group.
- If N is in Group 1, then O is in Group 2.
- P and Q must be in the same group.
Suppose P and Q are placed in Group 1. It could be true that both N and O are also in Group 1.
Is this statement true or false?
Correct answer: B
This statement is false. The rule states: if N is in Group 1, then O must be in Group 2. Therefore, N and O cannot both be in Group 1 — placing N in Group 1 forces O into Group 2, making it impossible for both to occupy Group 1 simultaneously. This is a direct application of the conditional rule: the consequent (O in Group 2) directly contradicts the scenario of O being in Group 1. The contrapositive confirms this: if O is in Group 1, then N cannot be in Group 1. Whether P and Q are in Group 1 is irrelevant to this constraint — N and O can never coexist in Group 1 regardless of other placements.
Question 7medium
Seven books — A, B, C, D, E, F, and G — are arranged on a shelf in positions 1 through 7 from left to right. The following rules apply:
- A is to the left of C.
- C is to the left of E.
- B is to the left of D.
- D is to the left of F.
Given these rules, it must be true that A is to the left of E.
Is this statement true or false?
Correct answer: A
This statement is true. The rules establish a chain of relative ordering: A is left of C, and C is left of E. By transitivity, A must be to the left of E in every valid arrangement — there is no possible configuration where A appears to the right of E without violating at least one of the two given rules. This is a core feature of relative ordering rules: when A < C and C < E (using '<' to mean 'is left of'), it necessarily follows that A < E. This transitive inference is one of the most important reasoning tools in linear sequencing games, and recognizing such chains quickly is essential for solving these games efficiently.
Question 8medium
Six students — L, M, N, O, P, and Q — are each assigned to exactly one of two study groups: Group 1 or Group 2. Each group must have at least two students. The following conditions apply:
- If L is in Group 1, then M is in Group 2.
- N and O must be in the same group.
- P must be in Group 1.
- Q cannot be in the same group as M.
If N is in Group 1, which of the following could be a complete and accurate list of the students in Group 2?
- A.L, Q✓
- B.L, M, Q
- C.M, Q
- D.M, L, O
Correct answer: A
If N is in Group 1, then O must also be in Group 1 (they must be in the same group). P is fixed in Group 1. So Group 1 contains at least N, O, and P. The remaining students — L, M, and Q — are distributed between the groups. The rule states Q cannot be in the same group as M, so M and Q must be in different groups. Option C places L, M, and Q all in Group 2, which puts M and Q together — a violation. Option A places M and Q both in Group 2 — also a violation of the Q/M rule. Option D places O in Group 2, but O must be with N in Group 1 — a violation. Option A places L and Q in Group 2 and M in Group 1: N, O, P, M are in Group 1; L and Q are in Group 2. L is not in Group 1, so the L→M rule doesn't trigger. Q and M are in different groups. All conditions are satisfied.
Question 9medium
Seven books — A, B, C, D, E, F, and G — are arranged on a shelf in positions 1 through 7 from left to right. The following conditions apply:
- A is somewhere to the left of D.
- B is somewhere to the left of E.
- C is in position 4.
- F and G are on opposite sides of C (one is in positions 1–3, the other is in positions 5–7).
Which of the following could be true?
- A.A is in position 6 and D is in position 2.
- B.B is in position 5 and E is in position 7.✓
- C.F is in position 2 and G is in position 3.
- D.C is in position 3.
Correct answer: B
Option A requires A to be to the left of D, but position 6 is to the right of position 2, so A in 6 and D in 2 means A is to the RIGHT ofD— a direct violation. Option B places both F and G on the left side ofB(positions 1–3), violating the rule that they must be on opposite sides of C. Option D states B is in position 3, but B is fixed in position 4 — a direct violation. Option B places C in position 5 and E in position 7:C(5) is to the left ofE(7), satisfying the B-before-E rule.Bremains in position 4, F and G can be placed on opposite sides, and A can be placed to the left of D without conflict. Option B could be true.
Question 10medium
A journalist is assigning five reporters — R, S, T, U, and V — to cover exactly three stories: Story 1, Story 2, and Story 3. Each story must have at least one reporter, and each reporter covers exactly one story. The following conditions apply:
- R and S cannot cover the same story.
- T must cover Story 2.
- If U covers Story 1, then V covers Story 3.
- V cannot cover Story 2.
If R covers Story 1, which of the following must be true?
- A.S covers Story 3.
- B.U covers Story 2.
- C.S covers Story 2 or Story 3.✓
- D.V covers Story 1.
Correct answer: C
If R covers Story 1, then S cannot cover Story 1 (R and S cannot share a story). Therefore S must cover Story 2 or Story 3, which makes option C necessarily true. Option A (S covers Story 3) is not required — S could cover Story 2 instead, so this is only possible, not necessary. Option B (U covers Story 2) is not required — U could cover Story 1 (which would force V to Story 3) or Story 3 as well. OptionC(V covers Story 1) is not required — V cannot cover Story 2, but V could cover Story 1 or Story 3. Since the only firm deduction from R being in Story 1 is that S must go to Story 2 or Story 3, option C is the one that must be true.